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14p^2-45p+25=0
a = 14; b = -45; c = +25;
Δ = b2-4ac
Δ = -452-4·14·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-25}{2*14}=\frac{20}{28} =5/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+25}{2*14}=\frac{70}{28} =2+1/2 $
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